MathDB
Sum of floors with primes p,q

Source: Baltic Way 2001

November 17, 2010
floor functioncombinatorics proposedcombinatorics

Problem Statement

Let pp and qq be two different primes. Prove that pq+2pq+3pq++(q1)pq=12(p1)(q1)\left\lfloor\frac{p}{q}\right\rfloor+\left\lfloor\frac{2p}{q}\right\rfloor+\left\lfloor\frac{3p}{q}\right\rfloor+\ldots +\left\lfloor\frac{(q-1)p}{q}\right\rfloor=\frac{1}{2}(p-1)(q-1)