MathDB
Ceil function [Iran Second Round 1995]

Source:

November 25, 2010
functionceiling functionquadraticsnumber theory proposednumber theory

Problem Statement

Let n≥0n \geq 0 be an integer. Prove that ⌈n+n+1+n+2⌉=⌈9n+8⌉ \lceil \sqrt n +\sqrt{n+1}+\sqrt{n+2} \rceil = \lceil \sqrt{9n+8} \rceil Where ⌈x⌉\lceil x \rceil is the smallest integer which is greater or equal to x.x.
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