MathDB

(m+n)\(a_m + a_n) for any m\ne n => n\a_n for any n

Source: St. Petersburg 2016 11.1

May 1, 2019

number theorySequencedivisornumber theory with sequencesInteger sequence

Problem Statement

In the sequence of integers

(a_n)

, the sum

a_m + a_n

is divided by

m + n

with any different

m

and

n

. Prove that

a_n

is a multiple of

n

for any

n