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Another early logarithm

Source: AIME II 2024 Problem 4

February 8, 2024
AMCAIMEalgebrasystem of equationsnumber theoryrelatively primeAIME II

Problem Statement

Let x,yx,y and zz be positive real numbers that satisfy the following system of equations: log2(xyz)=12\log_2\left({x \over yz}\right) = {1 \over 2} log2(yxz)=13\log_2\left({y \over xz}\right) = {1 \over 3} log2(zxy)=14\log_2\left({z \over xy}\right) = {1 \over 4}
Then the value of log2(x4y3z2)\left|\log_2(x^4y^3z^2)\right| is mn{m \over n} where mm and nn are relatively prime positive integers. Find m+nm+n