MathDB
a^2+b^2+c^2 divides a!+b!+c!

Source: Malaysian IMO TST 2023 P4

April 30, 2023
number theory

Problem Statement

Do there exist infinitely many triples of positive integers (a,b,c)(a, b, c) such that aa, bb, cc are pairwise coprime, and a!+b!+c!a! + b! + c! is divisible by a2+b2+c2a^2 + b^2 + c^2?
Proposed by Anzo Teh Zhao Yang
Back to ProblemsView on AoPS