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Rectangular Field

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February 1, 2009
geometryperimeter

Problem Statement

A rectangular field is half as wide as it is long and is completely enclosed by x x yards of fencing. The area in terms of x x is: <spanclass=′latex−bold′>(A)</span> x22<spanclass=′latex−bold′>(B)</span> 2x2<spanclass=′latex−bold′>(C)</span> 2x29<spanclass=′latex−bold′>(D)</span> x218<spanclass=′latex−bold′>(E)</span> x272 <span class='latex-bold'>(A)</span>\ \frac {x^2}{2} \qquad<span class='latex-bold'>(B)</span>\ 2x^2 \qquad<span class='latex-bold'>(C)</span>\ \frac {2x^2}{9} \qquad<span class='latex-bold'>(D)</span>\ \frac {x^2}{18} \qquad<span class='latex-bold'>(E)</span>\ \frac {x^2}{72}
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