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AB= CE wanted, starting with a 90-54-36 triangle

Source: 2015 Moldova JBMO TST 2.3

July 11, 2020
geometryright triangleequal segments

Problem Statement

In a right triangle ABCABC with BAC=90o\angle BAC =90^o and ABC=54o\angle ABC= 54^o, point MM is the midpoint of the hypotenuse [BC][BC] , point DD is the foot of the angle bisector drawn from the vertex CC and AMCD={E}AM \cap CD = \{E\}. Prove that AB=CEAB= CE.