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S + V = H + 3 in a closed rectangular neighborhood

Source: Flanders Math Olympiad 2017 p3

December 24, 2022
combinatorics

Problem Statement

In a closed rectangular neighborhood there are: SS streets (these are straight roads of maximum length), VV four-arm intersections ( https://cdn.artofproblemsolving.com/attachments/e/4/6a5974a30dc182b59a519a8ef4eb4f1412e05e.png), HH city blocks (these are rectangular areas bounded by four streets, which are no be intersected by another street) and TT represents the number of TT-intersections (https://cdn.artofproblemsolving.com/attachments/0/a/b390a30a0b27d83db681f70f633bdeed697163.png ). For example, in the neighborhood below, there are 1515 streets, 88 four-arm intersections, 2020 city blocks and 2222 TT-intersections. https://cdn.artofproblemsolving.com/attachments/a/2/c1a5e463d0fb5671ac0702c91cfc2272d4e2c3.png Prove that in each district S+V=H+3S + V = H + 3.