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symmetrical with respect to the circumcenter

Source: Spanish Mathematical Olympiad. 2015. Problem 2

April 30, 2015
geometryincentercircumcircle

Problem Statement

In triangle ABCABC, let AA' is the symmetrical of AA with respect to the circumcenter OO of ABCABC. Prove that: a) The sum of the squares of the tangents segments drawn from AA and AA' to the incircle of ABCABC equals 4R24Rr2r24R^2-4Rr-2r^2 where RR and rr are the radii of the circumscribed and inscribed circles of ABCABC respectively. b) The circle with center AA' and radius AIA'I intersects the circumcircle of ABCABC in a point LL such that AL=AB.ACAL=\sqrt{ AB.AC} where II is the centre of the inscribed circle of ABCABC.