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0,a_1a_2... rational ? if a_{n+1}=[3a_n/2], a_1=2

Source: 2006 VMEO III Shortlist SL A10 Vietnamese Mathematics e - Olympiad https://artofproblemsolving.com/community/c2461015_vme

November 24, 2021
algebrarationalSequencefloor function

Problem Statement

Let an{a_n} be a sequence defined by a1=2a_1=2, an+1=[3an2]a_{n+1}=\left[ \frac {3a_n}{2}\right] nN\forall n \in \mathbb N
0.a1a2...0.a_1a_2... rational or irrational?