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Soros Olympiad in Mathematics
II Soros Olympiad 1995 - 96 (Russia)
9.1
(x+1)^2-5(x+1) \sqrt{x}+4x=0 (II Soros Olympiad 1995-96 R2 9.1)
(x+1)^2-5(x+1) \sqrt{x}+4x=0 (II Soros Olympiad 1995-96 R2 9.1)
Source:
June 3, 2024
algebra
Problem Statement
Solve the equation
(
x
+
1
)
2
−
5
(
x
+
1
)
x
+
4
x
=
0
(x+1)^2-5(x+1) \sqrt{x}+4x=0
(
x
+
1
)
2
−
5
(
x
+
1
)
x
+
4
x
=
0
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