MathDB
easy, but yet an uncanny level of difficulty

Source: Romanian ROM TST 2004, problem 9, created by Harazi

May 3, 2004
pigeonhole principlelinear algebramatrixinequalitiescombinatorics solvedcombinatorics

Problem Statement

Let n2n\geq 2 be a positive integer, and XX a set with nn elements. Let A1,A2,,A101A_{1},A_{2},\ldots,A_{101} be subsets of XX such that the union of any 5050 of them has more than 5051n\frac{50}{51}n elements. Prove that among these 101101 subsets there exist 33 subsets such that any two of them have a common element.