MathDB
AO = OC wanted, <DBA = <CBP, # ABCD

Source: Polish Math Olympiad 2021 2nd round p2 day 1

May 31, 2021
equal segmentsparallelogramequal anglesgeometry

Problem Statement

The point P lies on the side CDCD of the parallelogram ABCDABCD with DBA=CBP\angle DBA = \angle CBP. Point OO is the center of the circle passing through the points DD and PP and tangent to the straight line ADAD at point DD. Prove that AO=OCAO = OC.