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2^{2n} + 2^n + 5 divisible by 5 (HOMC 2010 J Q2)

Source:

July 25, 2019
number theorydivisible

Problem Statement

Find the number of integer nn from the set {2000,2001,...,2010}\{2000,2001,...,2010\} such that 22n+2n+52^{2n} + 2^n + 5 is divisible by 77
(A): 00, (B): 11, (C): 22, (D): 33, (E) None of the above.