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4
Quadratics Again
Quadratics Again
Source:
February 24, 2006
quadratics
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Problem Statement
Find the positive solution to
1
x
2
−
10
x
−
29
+
1
x
2
−
10
x
−
45
−
2
x
2
−
10
x
−
69
=
0
\frac 1{x^2-10x-29}+\frac1{x^2-10x-45}-\frac 2{x^2-10x-69}=0
x
2
−
10
x
−
29
1
+
x
2
−
10
x
−
45
1
−
x
2
−
10
x
−
69
2
=
0
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