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b^2+a-1 has two divisors- Iran 3rd round-Number Theory 2007

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July 28, 2010
number theory unsolvednumber theory

Problem Statement

Let a,ba,b be two positive integers and b2+a−1∣a2+b−1b^2+a-1|a^2+b-1. Prove that b2+a−1b^2+a-1 has at least two prime divisors.
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