MathDB
The fraction has a limit - [Iran Second Round 1988]

Source:

December 7, 2010
algebrapolynomialinductionfactorialalgebra proposed

Problem Statement

(a) Prove that for all positive integers m,nm,n we have k=1nk(k+1)(k+2)(k+m1)=n(n+1)(n+2)(n+m)m+1\sum_{k=1}^n k(k+1)(k+2)\cdots (k+m-1)=\frac{n(n+1)(n+2) \cdots (n+m)}{m+1}
(b) Let P(x)P(x) be a polynomial with rational coefficients and degree m.m. If nn tends to infinity, then prove that k=1nP(k)nm+1\frac{\sum_{k=1}^n P(k)}{n^{m+1}} Has a limit.