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k = d (a) = d (b) = d (2a + 3b), no of positive divisors

Source: 2020 Dutch IMO TST 3.1

November 22, 2020
number theorynumber of divisors

Problem Statement

For a positive number nn, we write d(n)d (n) for the number of positive divisors of nn. Determine all positive integers kk for which exist positive integers aa and bb with the property k=d(a)=d(b)=d(2a+3b)k = d (a) = d (b) = d (2a + 3b).