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2023 MOAA
11
2023 MOAA Gunga P11
2023 MOAA Gunga P11
Source:
October 15, 2023
MOAA 2023
Problem Statement
Let
s
(
n
)
s(n)
s
(
n
)
denote the sum of the digits of
n
n
n
and let
p
(
n
)
p(n)
p
(
n
)
be the product of the digits of
n
n
n
. Find the smallest integer
k
k
k
such that
s
(
k
)
+
p
(
k
)
=
49
s(k)+p(k)=49
s
(
k
)
+
p
(
k
)
=
49
and
s
(
k
+
1
)
+
p
(
k
+
1
)
=
68
s(k+1)+p(k+1)=68
s
(
k
+
1
)
+
p
(
k
+
1
)
=
68
.Proposed by Anthony Yang
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