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Iran National Math Olympiad-Day 2-Problem 5

Source:

April 30, 2010
geometrycircumcircletrigonometryvectorangle bisectorIran

Problem Statement

In triangle ABCABC we havev A=π3\angle A=\frac{\pi}{3}. Construct EE and FF on continue of ABAB and ACAC respectively such that BE=CF=BCBE=CF=BC. Suppose that EFEF meets circumcircle of ACE\triangle ACE in KK. (K≢EK\not \equiv E). Prove that KK is on the bisector of A\angle A.