MathDB
OI is perpendicular to DE

Source: China TST 1988, problem 3

June 27, 2005
geometrycircumcircleincentergeometry solved

Problem Statement

In triangle ABCABC, C=30\angle C = 30^{\circ}, OO and II are the circumcenter and incenter respectively, Points DACD \in AC and EBCE \in BC, such that AD=BE=ABAD = BE = AB. Prove that OI=DEOI = DE and OIDEOI \bot DE.