MathDB
Problem on irrationals...... [ISI(BS) 06#2]

Source:

June 2, 2012
quadratics

Problem Statement

Suppose that aa is an irrational number.
(a) If there is a real number bb such that both (a+b)(a+b) and abab are rational numbers, show that aa is a quadratic surd. (aa is a quadratic surd if it is of the form r+sr+\sqrt{s} or rsr-\sqrt{s} for some rationals rr and ss, where ss is not the square of a rational number).
(b) Show that there are two real numbers b1b_1 and b2b_2 such that
i) a+b1a+b_1 is rational but ab1ab_1 is irrational.
ii) a+b2a+b_2 is irrational but ab2ab_2 is rational. (Hint: Consider the two cases, where aa is a quadratic surd and aa is not a quadratic surd, separately).