MathDB
k-regular triangle-free graphs are halfways bipartite

Source: Glenn Hopkins in Ars Combinatoria; used in the 4th QEDMO

March 6, 2007
combinatorics proposedcombinatorics

Problem Statement

A team contest between nn participants is to be held. Each of these participants has exactly kk enemies among the other participants. (If AA is an enemy of BB, then BB is an enemy of AA. Nobody is his own enemy.) Assume that there are no three participants such that every two of them are enemies of each other. A subversive enmity will mean an (un-ordered) pair of two participants which are enemies of each other and which belong to one and the same team. Show that one can divide the participants into two teams such that the number of subversive enmities is k(n2k)2\leq\frac{k\left(n-2k\right)}{2}. (The teams need not be of equal size.) Note. The actual source of this problem is: Glenn Hopkins, William Staton, Maximal Bipartite Subgraphs, Ars Combinatoria 13 (1982), pp. 223-226. It should be noticed that k(n2k)2n216\frac{k\left(n-2k\right)}{2}\leq\frac{n^{2}}{16}, so the bound in the problem can be replaced by n216\frac{n^{2}}{16} (which makes it weaker, but independent of kk). darij