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Concave Heptagon with Square Components

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September 8, 2024
geometry2024

Problem Statement

Let N11N_{11} be the answer to problem 11.
Concave heptagon HOPKINSHOPKINS, where 180∘<∠HOP<270∘180^\circ<\angle HOP<270^\circ, has area N11N_{11}, and HP=NI24HP=NI\sqrt{24}. Suppose that HONSHONS and OPKIOPKI are congruent squares. Compute the common area of each of these squares.
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