MathDB
Problem B2

Source: 2019 Malaysia OMK

August 21, 2019
geometry

Problem Statement

Given a parallelogram ABCDABCD, a point M is chosen such that DAC=MAC\angle DAC=\angle MAC and CAB=MAB.\angle CAB=\angle MAB. Prove AMBM=(ACBD)2\frac{AM}{BM}=\left(\frac{AC}{BD}\right)^2