MathDB
Equilateral triangle

Source: 2020 Taiwan TST

March 29, 2020
geometry proposedgeometry

Problem Statement

Let OO be the center of the equilateral triangle ABCABC. Pick two points P1P_1 and P2P_2 other than BB, OO, CC on the circle (BOC)\odot(BOC) so that on this circle BB, P1P_1, P2P_2, OO, CC are placed in this order. Extensions of BP1BP_1 and CP1CP_1 intersects respectively with side CACA and ABAB at points RR and SS. Line AP1AP_1 and RSRS intersects at point Q1Q_1. Analogously point Q2Q_2 is defined. Let (OP1Q1)\odot(OP_1Q_1) and (OP2Q2)\odot(OP_2Q_2) meet again at point UU other than OO.
Prove that 2Q2UQ1+Q2OQ1=3602\,\angle Q_2UQ_1 + \angle Q_2OQ_1 = 360^\circ.
Remark. (XYZ)\odot(XYZ) denotes the circumcircle of triangle XYZXYZ.