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inequality when a_{n+1} = \sqrt{a_n^2 + 1/a_n }

Source: 1988 Swedish Mathematical Competition p6

March 28, 2021
inequalitiesalgebraSequencerecurrence relationradical

Problem Statement

The sequence (an)(a_n) is defined by a1=1a_1 = 1 and an+1=an2+1ana_{n+1} = \sqrt{a_n^2 +\frac{1}{a_n}} for n1n \ge 1. Prove that there exists aa such that 12anna2\frac{1}{2} \le \frac{a_n}{n^a} \le 2 for n1n \ge 1.