Prove this trigonometric inequality with complex numbers
Source: 2019 Jozsef Wildt International Math Competition
May 19, 2020
inequalitiestrigonometrycomplex numbers
Problem Statement
Consider the complex numbers a1,a2,⋯,an, n≥2. Which have the following properties:[*] ∣ai∣=1∀i=1,2,⋯,n
[*] k=1∑narg(ak)≤πShow that the inequality(n2cot(2nπ))−1k=0∑n(−1)k[3n2−(8k+5)n+4k(k+1)σk]≥(1+n1)2cot2(2nπ)+16k=0∑n(−1)kσkwhere σ0=1, σk=1≤i1≤i2≤⋯≤ik≤n∑ai1ai2⋯aik, ∀k=1,2,⋯,n