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y =\sqrt{x^3+1},y=-\sqrt[3]{x^2+ 2x} (V Soros Olympiad 1998-99 Round 3 11.3)

Source:

May 26, 2024

analytic geometrygeometryareas

Problem Statement

Find the area of the figure on the coordinate plane bounded by the straight lines

x = 0

x = 2

and the graphs of the functions

y =\sqrt{x^3+ 1}

and

y = - \sqrt[3]{x^2+ 2x}