MathDB
Angle bisector in a rectangle

Source: Tuymaada 2012, Problem 2, Day 1, Juniors

July 21, 2012
geometryrectanglesymmetryangle bisectorgeometry proposed

Problem Statement

A rectangle ABCDABCD is given. Segment DKDK is equal to BDBD and lies on the half-line DCDC. MM is the midpoint of BKBK. Prove that AMAM is the angle bisector of ∠BAC\angle BAC.
Proposed by S. Berlov
Back to ProblemsView on AoPS