MathDB
Today's calculation of Integral 84

Source: 1993 Kochi University Entrance exam

September 27, 2005
calculusintegrationlimittrigonometrycalculus computations

Problem Statement

Evaluate lim⁡n→∞n∫0πe−nxsin⁡2nx dx\lim_{n\to\infty} n\int_0^\pi e^{-nx} \sin ^ 2 nx\ dx
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