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Iran geometry

Source: Iranian TST 2018, first exam, day1, problem 3

April 7, 2018
geometry

Problem Statement

In triangle ABCABC let MM be the midpoint of BCBC. Let ω\omega be a circle inside of ABCABC and is tangent to AB,ACAB,AC at E,FE,F, respectively. The tangents from MM to ω\omega meet ω\omega at P,QP,Q such that PP and BB lie on the same side of AMAM. Let XPMBFX \equiv PM \cap BF and YQMCEY \equiv QM \cap CE . If 2PM=BC2PM=BC prove that XYXY is tangent to ω\omega.
Proposed by Iman Maghsoudi