MathDB
2012-2013 Winter OMO #34

Source:

January 16, 2013
Online Math Opennumber theoryrelatively prime

Problem Statement

For positive integers nn, let s(n)s(n) denote the sum of the squares of the positive integers less than or equal to nn that are relatively prime to nn. Find the greatest integer less than or equal to ∑n∣2013s(n)n2, \sum_{n\mid 2013} \frac{s(n)}{n^2}, where the summation runs over all positive integers nn dividing 20132013.
Ray Li
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