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Tie 1
2021 BMT Algebra Tiebreaker #1
2021 BMT Algebra Tiebreaker #1
Source:
March 10, 2024
algebra
Problem Statement
Let the sequence
{
a
n
}
\{a_n\}
{
a
n
}
for
n
≥
0
n \ge 0
n
≥
0
be defined as
a
0
=
c
a_0 = c
a
0
=
c
, and for
n
≥
0
n \ge 0
n
≥
0
,
a
n
=
2
a
n
−
1
4
a
n
−
1
2
−
1
.
a_n =\frac{2a_{n-1}}{4a^2_{n-1} -1}.
a
n
=
4
a
n
−
1
2
−
1
2
a
n
−
1
.
Compute the sum of all values of
c
c
c
such that
a
2020
a_{2020}
a
2020
exists but
a
2021
a_{2021}
a
2021
does not exist.
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