If the square of a number of two digits is decreased by the square of the number formed by reversing the digits, then the result is not always divisible by:
<spanclass=′latex−bold′>(A)</span>9<spanclass=′latex−bold′>(B)</span>the product of the digits<spanclass=′latex−bold′>(C)</span>the sum of the digits<spanclass=′latex−bold′>(D)</span>the difference of the digits<spanclass=′latex−bold′>(E)</span>11