MathDB
(a^2+b^2)/(2a^5b^5) + (81a^2b^2)/4 + 9ab \geq 81

Source: Bulgaria JBMO TST 2018, Day 1, Problem 2

June 25, 2018
inequalities

Problem Statement

For all positive reals aa and bb, show that a2+b22a5b5+81a2b24+9ab>18.\frac{a^2+b^2}{2a^5b^5} + \frac{81a^2b^2}{4} + 9ab > 18.