MathDB
PA_1+PA_3+PA_5+PA_7 = PA_2+PA_4+PA_6 in regular heptagon

Source: Austrian-Polish 1984

May 25, 2019
geometryHeptagonregular polygon

Problem Statement

A regular heptagon A1A2...A7A_1A_2... A_7 is inscribed in circle CC. Point PP is taken on the shorter arc A7A1A_7A_1. Prove that PA1+PA3+PA5+PA7=PA2+PA4+PA6PA_1+PA_3+PA_5+PA_7 = PA_2+PA_4+PA_6.
Back to ProblemsView on AoPS