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Polish MO Finals
1954 Polish MO Finals
2
ctg A + \frac{cos B}{sin A cos C} = ctg B + \frac{cos A}{sin B cos C}.
ctg A + \frac{cos B}{sin A cos C} = ctg B + \frac{cos A}{sin B cos C}.
Source: Polish MO Finals 1954 p2
August 29, 2024
trigonometry
Problem Statement
What algebraic relationship holds between
A
A
A
,
B
B
B
, and
C
C
C
if
c
t
g
A
+
cos
B
sin
A
cos
C
=
c
t
g
B
+
cos
A
sin
B
cos
C
.
ctg A + \frac{\cos B}{\sin A \cos C} = ctg B + \frac{\cos A}{\sin B \cos C}.
c
t
g
A
+
sin
A
cos
C
cos
B
=
c
t
g
B
+
sin
B
cos
C
cos
A
.
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