Compute the number of possible words w=w1w2…w100 satisfying:
∙w has exactly 50A's and 50B's (and no other letter).
∙ For i=1,2,…,100, the number of A's among w1,w2,…,wi is at most the number of B's among w1,w2,…,wi.
∙ For all i=44,45,…,57, if wi is a B, then wi+1 must be a B.