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1
SMT 2018 Geometry Tiebreaker #1
SMT 2018 Geometry Tiebreaker #1
Source:
August 8, 2023
geometry
Problem Statement
Point
E
E
E
is on side
C
D
CD
C
D
of rectangle
A
B
C
D
ABCD
A
BC
D
such that
C
E
D
E
=
2
5
.
\frac{CE}{DE} =\frac{2}{5}.
D
E
CE
=
5
2
.
If the area of triangle
B
C
E
BCE
BCE
is
30
30
30
, what is the area of rectangle
A
B
C
D
ABCD
A
BC
D
?
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