Given the binary operation ∗ defined by a∗b=ab for all positive numbers a and b. The for all positive a,b,c,n, we have<spanclass=′latex−bold′>(A)</span>a∗b=b∗a<spanclass=′latex−bold′>(B)</span>a∗(b∗c)=(a∗b)∗c<spanclass=′latex−bold′>(C)</span>(a∗bn)=(a∗n)∗b<spanclass=′latex−bold′>(D)</span>(a∗b)n=a∗(bn)<spanclass=′latex−bold′>(E)</span>None of these