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Tuymaada 2010, Junior League, Problem 2

Source:

July 18, 2010
geometrycircumcirclegeometric transformationreflectionparallelogramcalculustrigonometry

Problem Statement

Let ABCABC be an acute triangle, HH its orthocentre, DD a point on the side [BC][BC], and PP a point such that ADPHADPH is a parallelogram. Show that ∠BPC>∠BAC\angle BPC > \angle BAC.
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