MathDB
Funny Function

Source:

March 25, 2006
function

Problem Statement

If F(n+1)=2F(n)+12F(n+1)=\frac{2F(n)+1}{2} for n=1,2,n=1,2,\ldots, and F(1)=2F(1)=2, then F(101)F(101) equals: (A) 49(B) 50(C) 51(D) 52(E) 53\text{(A)} \ 49 \qquad \text{(B)} \ 50 \qquad \text{(C)} \ 51 \qquad \text{(D)} \ 52 \qquad \text{(E)} \ 53