MathDB
2023 China TST Problem 13

Source: 2023 China TST Problem 13

March 27, 2023
number theory

Problem Statement

Does there exists a positive irrational number x,{x}, such that there are at most finite positive integers n,{n}, satisfy that for any integer 1≤k≤n,1\leq k\leq n, {kx}≥1n+1?\{kx\}\geq\frac 1{n+1}?
Back to ProblemsView on AoPS