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sovle x*36 = 216 if a*(b*c) = (a*b)c$ and $a*a = 1$

Source: 1993 Swedish Mathematical Competition p4

April 2, 2021
algebraequation

Problem Statement

To each pair of nonzero real numbers aa and bb a real number aba*b is assigned so that a(bc)=(ab)ca*(b*c) = (a*b)c and aa=1a*a = 1 for all a,b,ca,b,c. Solve the equation x36=216x*36 = 216.