MathDB

Today's calculation of Integral 39

Source: 1990 Tokyo Institute of Technology

June 9, 2005

calculusintegrationfunctiontrigonometrylogarithmscalculus computations

Problem Statement

Find the minimum value of the following function

f(x)

defined at

0<x<\frac{\pi}{2}

f(x)=\int_0^x \frac{d\theta}{\cos \theta}+\int_x^{\frac{\pi}{2}} \frac{d\theta}{\sin \theta}