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A nice Inequality

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October 22, 2010
inequalitiesrearrangement inequalityinequalities unsolved

Problem Statement

For any positive real numbers a,b,ca, b, c, prove that
cyclic(b+c)(a4b2c2)ab+2bc+ca0\sum_{cyclic} \frac{(b + c)(a^4 - b^2 c^2 )}{ab + 2bc + ca} \ge 0