5-digit numbers with even number of digits are even.
Source: 0
April 28, 2009
Problem Statement
Let A be the numbers of 5-digit positive numbers satisfying following condition:
The first digit is odd. Remaining 0, or 2 or 4 digit/digits are even.Let B be the numbers of 5-digit positive numbers satisfying following condition:
The first digit is even. Remaining 0, or 2 or 4 digit/digits are even. A \minus{} B \equal{} ?<spanclass=′latex−bold′>(A)</span>5000<spanclass=′latex−bold′>(B)</span>4640<spanclass=′latex−bold′>(C)</span>3200<spanclass=′latex−bold′>(D)</span>0<spanclass=′latex−bold′>(E)</span>None