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Proof of being Circumcenter of APQ from JMO 2010

Source: 2010 Japan Mathematical Olympiad Finals, Problem 1

February 11, 2010
geometrycircumcircleincenterperpendicular bisectorgeometry proposed

Problem Statement

Given an acute-angled triangle ABC ABC such that ABAC AB\neq AC. Draw the perpendicular AH AH from A A to BC BC. Suppose that if we take points P, Q P,\ Q in such a way that three points A, B, P A,\ B,\ P and three points A, C, Q A,\ C,\ Q are collinear in this order respectively, then we have four points B, C, P, Q B,\ C,\ P,\ Q are concyclic and HP \equal{} HQ. Prove that H H is the circumcenter of APQ \triangle{APQ}.