MathDB
Fifth problem

Source: Cono sur 2018

August 27, 2018
geometryincentercircumcirclecono sur

Problem Statement

Let ABCABC be an acute-angled triangle with BAC=60\angle BAC = 60^{\circ} and with incenter II and circumcenter OO. Let HH be the point diametrically opposite(antipode) to OO in the circumcircle of BOC\triangle BOC. Prove that IH=BI+ICIH=BI+IC.